Mathématiques

Question

simplier l'expression suivante:
a/(a-b)(a-c)+b/(b-a)(b-c)+c/(c-a)(c-b)=?

1 Réponse

  • a/(a-b)(a-c) + b/(b-a)(b-c)+c/(c-a)(c-b)=
    a/(a-b)(a-c) + b/-(a-b)(b-c) +c/(a-c)(b-c)=
    a/(a-b)(a-c) - b/(a-b)(b-c) +c/(a-c)(b-c)=
    a(b-c)/(a-b)(a-c)(b-c) - b(a-c) /(a-b)(b-c(a-c)) + c(a-b) /(a-c)(b-c)(a-b)=
    a(b-c) -b(a-c) +c(a-b)/(a-b)(a-c)(b-c)=
    ab-ac-ba+bc+ac-cb/(a-b)(a-c)(b-c)=0










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